Thermal Equilibirum Calorimeter

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TFM
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Question

A copper calorimeter can with mass 0.100 kg contains 0.160 kg of water and 0.018 kg of ice in thermal equilibrium at atmospheric pressure.

If 0.750 kg of lead at a temperature of 255 degrees C is dropped into the calorimeter can, what is the final temperature? Assume that no heat is lost to the surroundings.

Related Formula

[tex]Q_1 + Q_2 + Q_3 = 0[/tex]

[tex]Q = mc\Delta T[/tex]

[tex]\Delta T = T_{initial} - T_{final}[/tex]

The initial temperature of the Ice/Water/Container, so I am not quite sure what the best way to start this question is.

Any suggestions?

TFM
 
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Please post your problems in the correct forum in future

As for your question, I offer you a hint: what is the temperature at which ice and water exists at thermal equilibrium?
 
Sorry, I htought there was something different:blushing: Feel free to move to 'Homework and Coursework: Introductory Physics' Category.

Would this be at the Triple point, which I is 0.0098 degrees celsius, 273.1598 Kelvin. This must be the intial Temperature?
 
TFM said:
Would this be at the Triple point, which I is 0.0098 degrees celsius, 273.1598 Kelvin. This must be the intial Temperature?
Correct! :approve: