# Water equivalent of calorimeter

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1. Feb 26, 2015

### rasen58

1. The problem statement, all variables and given/known data
The water equivalent in kg, of a calorimeter having a mass of 0.3 kg and a specific heat of 0.2 is

2. Relevant equations
q=cmT

3. The attempt at a solution
I wanted to set cmT = cmT for the water and calorimeter, but I don't know what the equilibrium temperature is.
So what do I do?

2. Feb 26, 2015

### Bystander

That's good. Simplify what you set up, and you're in business.

3. Feb 26, 2015

### rasen58

Can I cancel out the T's then?
In that case, I would have c1m1 = c2m2
(0.2)(0.3) = (4.186)m2
m2 = 0.014 kg

But the answer says it's 0.06 kg

4. Feb 27, 2015

### Bystander

Yes.
You have met one of many sloppily stated questions you'll run into in your life. "Specific heat" has been conflated with "Specific gravity." Since water has a specific gravity of "One," the author of the question has chosen "One" as the specific heat for water as well. In kcal/kg, yes, but there is no specification of units in the problem statement.

Your understanding is correct, and your application of that understanding is correct.