1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Calculating Heat Capacity of Calorimeter

  1. Dec 26, 2014 #1
    Need a little help, as I seem to have gotten confused.
    Looking over past exam questions for the heat capacity of a calorimeter, this one is the one im looking at :


    A sample of the sugar fructose (C6H12O6) of mass 0.900 gwas placed in a calorimeter and
    ignited inthe presence of excess oxygen, at the saturation vapour pressure of water and at
    constant volume.The temperature rose by 1.4 K.
    The calorimeter had previously been calibrated by passing an electrical current through a heating
    tape for 100 s. The power supplied to the tape was 500 W and the temperature of the calorimeter
    rose by 5 K


    Right. The reason im confused, is the text book ive been reading from had similar worked examples, however they didn't have any values in watts. They have in Ampere and Volts.
    As far as im aware 1 watt is equal to 1j/s..


    So to work the heat capacity of the calorimeter,
    would i:


    1) 500W*60 to get to 8.3 J/s
    2) then multiply by 100s and divide by the 5K.
    3) then multiply this answer by 1.4k, to get 233.3 joules.
    4) Finally, divide by 1000, to get the heat capacity of the calorimeter at 0.23KJ?


    Or am I way off?
     
  2. jcsd
  3. Dec 26, 2014 #2

    Bystander

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Waayyy oofffffff.
    This is a clue.
    This is another clue. Hint, what's "Watt" mean, what are the units?
    Then, divide.
     
  4. Dec 26, 2014 #3
    The units of W is one Joule per second?, so If i multiply the 500W by the 100s. I get 50000 J?
    Do I then divide this by the 5K? Finally multiply by the 1.4k? to get the final answer at 14Kj?
     
  5. Dec 26, 2014 #4
    Or do I need not multiply by the 1.4k.

    Is it simply 500w x 100s/ 5k= 10,000J/1000= 10kJ??
     
  6. Dec 26, 2014 #5

    Bystander

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Why so uncertain?
    Upper case "K" denotes Kelvin, or degrees Kelvin (same size as C); you'll want lower case "k" to denote "kilo" or thousand; lower case "j" has a number of meanings, but none indicate Joule, or upper case "J." Other than that, you're in business.
     
  7. Dec 26, 2014 #6

    Bystander

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Now I know why you're uncertain. What's the definition of "heat capacity?"
     
  8. Dec 26, 2014 #7
    The amount of heat needed to raise the temperature of an object or substance by 1 degree.. So I don't need to multiply by 1.4k at the end?
    Just 500W x 100s/5k= Heat capacity of Calorimeter? so 10 kJ?

    Sorry its been a long day haha.
     
  9. Dec 26, 2014 #8

    Bystander

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Think. What are the units? You multiplied watts by seconds and got joules. If you divide joules by temperature, what do you get for units?
     
  10. Dec 26, 2014 #9
    I would of assumed J/K?
     
  11. Dec 26, 2014 #10

    Bystander

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Yes. Now, you know the heat capacity of the calorimeter. You know the temperature rise for a particular measurement. How do you calculate the heat released in that measurement?
     
  12. Dec 26, 2014 #11
    So now I just multiply it by the 1.4K? to get the amount of heat released as I had it in J/K. So as it was in Joules per kelvin, if i times by 1.4 Kelvin, the heat will adjust, so I will know how much?

    But the question was only asking for the heat capacity of the calorimeter? not how much heat was released? So im right in assuming, that for just the heat capacity of the calorimeter, I don't need to multiply by the 1.4K?
     
  13. Dec 26, 2014 #12

    Bystander

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    Correct.
     
  14. Dec 26, 2014 #13
    You were a massive help, really appreciate it!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Calculating Heat Capacity of Calorimeter
Loading...