Thermal Expansion (Area Expansion) problem help

Click For Summary
SUMMARY

The discussion focuses on a thermal expansion problem involving a steel ring and an aluminum rod. The steel ring has an area of 3.990 cm² and the aluminum rod has a cross-sectional area of 4.000 cm², both initially at 35.0°C. To determine the common temperature at which the steel ring can be slipped onto the aluminum rod, the equation for area expansion, delta A = yAodelaT, is utilized. The solution requires calculating the temperature change necessary for the areas to match, allowing the ring to fit over the rod.

PREREQUISITES
  • Understanding of thermal expansion concepts
  • Familiarity with the area expansion formula: delta A = yAodelaT
  • Basic knowledge of temperature scales and conversions
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Research the coefficients of linear and area expansion for steel and aluminum
  • Learn how to apply the area expansion formula in practical scenarios
  • Explore temperature conversion techniques relevant to thermal expansion problems
  • Study similar thermal expansion problems to reinforce understanding
USEFUL FOR

Students studying physics, particularly those focusing on thermodynamics and material properties, as well as educators seeking to enhance their teaching of thermal expansion concepts.

queennicolee
Messages
1
Reaction score
0

Homework Statement


A steel ring with a hole having area of 3.990 cm2 is to be placed on an aluminum rod with crosssectional area of 4.000 cm2. Both rod and ring are initially at a temperature of 35.0°C. At what common temperature can the steel ring be slipped onto one end of the aluminum rod?

Homework Equations


delta A = yAodelaT

T = To + deltaT

The Attempt at a Solution

 
Physics news on Phys.org
Please show an attempt that you made at solving the problem.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
24K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
5
Views
2K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K