Thermal expansion of a liquid in a cylindrical container

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SUMMARY

The discussion focuses on the relationship between the coefficient of linear thermal expansion of a liquid and the cylindrical container it occupies when heated. It establishes that the volume change of the liquid is related to the thermal expansion of both the container and the liquid itself. The derived equations show that the new volume of the liquid can be expressed as a function of the original volume and the coefficients of thermal expansion, leading to the conclusion that the linear expansion of the container significantly influences the liquid's behavior under temperature changes.

PREREQUISITES
  • Understanding of thermal expansion concepts, specifically linear and volumetric expansion.
  • Familiarity with the equations for volume change, such as ΔV = V₀ 3α ΔT.
  • Basic knowledge of cylindrical geometry and volume calculations.
  • Ability to manipulate algebraic expressions involving coefficients of thermal expansion.
NEXT STEPS
  • Research the coefficient of volumetric thermal expansion for various liquids.
  • Explore the effects of temperature on the physical properties of materials, particularly metals used in containers.
  • Study the derivation and applications of the equation ΔV = V₀ 3α ΔT in real-world scenarios.
  • Investigate the implications of thermal expansion in engineering applications, such as fluid storage and transport systems.
USEFUL FOR

Students studying thermodynamics, engineers involved in material selection for thermal applications, and researchers exploring fluid dynamics in heated environments.

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Homework Statement


There is liquid in a cylindrical container at some level. Now when the container is heated, the level of the liquid remains the same in the container. What is the relationship between the coefficient of linear thermal expansion of liquid and the container ?

Homework Equations


\Delta V = V_o 3\alpha \Delta T
\Delta l = l_o \alpha \Delta T

The Attempt at a Solution



Now as the temperature increases, all dimensions of the container increase. Its height increases and also its radius increases. Since liquid remains at the same level, does that mean that the change in volume for both of them is the same ? Please guide... If we mark the level of the liquid before heating by some marker, then the liquid remains at this marker position even after the heating.

Thanks
 
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What is the relevant equation for the liquid level h (as a function of V) ?
 
I think I found the answer... Let original radius of cylinder be r and original liquid marker position be x. Then the original volume of the liquid is
\pi r^2 x
Let new radius of the container be r' and new liquid marker position be x'. Let \alpha_c be the coefficient of the linear thermal expansion of the container and let \Delta T be the change in temperature.. Then we have
r' = r [ 1 + \alpha_c \Delta T]
x' = x [ 1 + \alpha_c \Delta T]

Now the new volume of the liquid is \pi r'^2 x'. Which is equal to
\pi r^2 [ 1 + \alpha_c(\Delta T)]^2 x [ 1 + \alpha_c(\Delta T)]
\pi r^2 x [ 1 + \alpha_c(\Delta T)]^3

So we have
\frac{V^{liquid}_{new}}{V^{liquid}_{old}} = [ 1 + \alpha_c(\Delta T)]^3

But the new volume of liquid is related to old volume of liquid by the relation involving the coefficient of volume thermal expansion of the liquid.

V^{liquid}_{new} = V^{liquid}_{old} [ 1 + \beta_{liq} (\Delta T)]

Comparing two equations, we get

1 + \beta_{liq} (\Delta T) = [ 1 + \alpha_c(\Delta T)]^3

Since \alpha_c is very small for most of the materials, we can drop higher order terms here.

1 + \beta_{liq} (\Delta T) \approx 1 + 3 \alpha_c(\Delta T)

Would this be correct ?
 

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