Thermal Physics, Homework #1 problem #1

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
9 replies · 3K views
scikris
Messages
13
Reaction score
0
Consider a large number N of localized particles in an external magnetic field H. Each particle has spin 1/2.

Find the number of states, g(N,M), accessible to the system as a function of M=(Nup-Ndown), the magnetization.

Calculate the entropy per particle.

Determine the value of M for which the number of states is a maximum for a given N.


Equations that may help?
N=Nup+Ndown

M=Nup-Ndown

g(N,s)= N!/(Nup!Ndown!)

σ(N,U)=log(g(N,U))



This is my first thermal physics course and I am kinda confused (and overwhelmed) by this first homework assignment if anyone could explain what I am suposed to do, or set me in a direction, I would appreciate it.

Thanks in advance,
Kris
 
Physics news on Phys.org
I should note, this homework is due tomorrow morning :(

any help appreciated!
 
Are you familiar with Stirling's Approximation:

[tex] \ln[N!]\approx N\ln[N]-N[/tex]
 
yes, the stirling's approximation just gives a means to calculate N! for very large N, but I still don't know how to apply that to entropy per particle...
 
Use the equations you are given:

[tex] \sigma=\ln\left[\frac{N!}{N_{up}!N_{down}!}\right]=\ln[N!]-\ln[N_{up}!]-\ln[N_{down}!][/tex]

Apply Stirling's approximation to the above, then use the fact that [itex]N=N_{up}+N_{down}[/itex] and [itex]M=N_{up}-N_{down}[/itex].
 
okay thank you!,

"Determine the value of M for which the number of states is a maximum for a given N."
The value of M should be 0 correct?, because the middle of the Gaussian distribution will be centered at the origin. M=Nup-Ndown
 
scikris said:
okay thank you!,

"Determine the value of M for which the number of states is a maximum for a given N."
The value of M should be 0 correct?, because the middle of the Gaussian distribution will be centered at the origin. M=Nup-Ndown

Correct, but I would say this as "the value of M will be zero because the maximum of the Gaussian distribution will be when [itex]N_{up}=N_{down}=N/2\rightarrow M=N_{up}-N_{down}=N_{up}-N_{up}=0[/itex]" rather than how you have it.
 
okay cool, your equation didnt show up could you re-post it?
 
That is weird, I thought \rightarrow worked here... It should read

[itex]N_{up}=N_{down}=N/2[/itex] --> [itex]M=N_{up}-N_{down}=N_{up}-N_{up}=0[/itex]
 
thanks, I think I have got it now.