Thermo Final Review - specific heat for ideal gas

AI Thread Summary
The discussion clarifies that the internal energy of an ideal gas, expressed as U = C_V T, is not limited to constant-volume processes, as internal energy is a state variable dependent solely on temperature. The term C_V in this context is a proportionality constant, not the specific heat capacity, and can be interpreted as the total heat capacity of the gas. The formula can also be represented as U = nC_V T, where n denotes the number of moles, making C_V the molar specific heat capacity. This understanding supports the conclusion that the correct answer to the posed question is "all of the above." Overall, the relationship between internal energy and temperature is key to grasping the concept for ideal gases.
dwsky
Messages
1
Reaction score
0
Thread moved from the technical forums to the schoolwork forums
TL;DR Summary: why is the answer "all of the above"?

Could someone explain why the correct answer is all of the above? I understand that Cv implies a constant volume process, but what about the other two?
1701587269400.png
 
Last edited by a moderator:
Physics news on Phys.org
Because internal energy of an ideal gas depends only on its temperature.
 
  • Like
Likes Chestermiller
dwsky said:
I understand that Cv implies a constant volume process, but what about the other two?
The fact that you can write the internal energy of an ideal gas as ##U = C_{_V} T## doesn't mean that this formula can only be used in constant-volume processes. Internal energy is a state variable and for an ideal gas ##U## is proportional to the absolute temperature. In the formula ##U = C_{_V} T##, think of ##C_{_V}## as just a number (with units) that gives the proportionality constant between ##U## and ##T##.

Note that in the formula ##U = C_{_V} T##, ##C_{_V}## is not the specific heat capacity. It's the total heat capacity which takes into account the amount of gas. Often, you see the formula written as ##U = nC_{_V} T## where ##n## is the number of moles and ##C_{_V}## now represents the molar specific heat capacity.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top