Is there any work done? Plug that value into your equation.keevenh said:Homework Statement
In a constant-volume process, 208 J of energy is transferred by heat to 0.99 mol of an ideal monatomic gas initially at 290 K.
(a) Find the work done on the gas.
(b) Find the increase in internal energy of the gas.
(c) Find its final temperature.
I just don't know which equation to use and don't really know which direction to take.
Homework Equations
Pretty sure it involves ΔU=W+Q
A thermodynamic constant volume process is a type of thermodynamic process in which the volume of a system remains constant throughout. This means that no work is done on or by the system, and all changes in energy are due to heat transfer.
A constant volume process is different from other thermodynamic processes, such as constant pressure or adiabatic processes, because the volume of the system remains constant. This means that the pressure and temperature of the system can change, but the volume will not.
The equation for calculating the change in internal energy during a constant volume process is ΔU = Q, where ΔU is the change in internal energy and Q is the heat transferred to the system.
A constant volume process is represented on a thermodynamic diagram as a vertical line, as the volume remains constant while the pressure and temperature may change.
Some real-world examples of constant volume processes include the heating of a closed container, where the volume of the container remains constant as the temperature inside increases, and the combustion of fuel in an internal combustion engine, where the volume of the cylinder remains constant as the fuel is ignited and expands to do work.