Thermodynamics: Isobaric process finding volume of steam.

[craglyboy]

Homework Statement

http://img140.imageshack.us/img140/2963/isobaricsteam.jpg

P1 and P2 are 1 bar. V2 4.812 and V2 specific volume is 2.406

X1=0.6

Homework Equations

v=vf+x(vf-vg)

W=-P(v2-v1)

Q=(u2+pv2)-(u1+pv1)

The Attempt at a Solution

Hi guys first timer here just looking where to start off, I guess I need to find out the specific volume to find out V1 but I am stumped at how to use the dryness fraction to do that any help would be greatly appreciated

 

[LawrenceC]

The dryness fraction is used to compute the specific volume before heating.

v=vf+x(vf-vg)

Is the above correct? Looks to me that you'll get a negative value for v because vg>vf.

You can compute v at the end of the process.

Apply first law.

 

[craglyboy]

thanks yeah that was just a typo supposed to be (Vg-Vf).

The thing is I don't know values Vg and Vf are I have looked up in my steam tables and it says Vg is 1.694 at 1 bar but what is Vf?

 

[craglyboy]

Is Vf zero?

 

[LawrenceC]

No, vf is not zero but it is quite a bit smaller than vg. My steam tables have 3 columns. One is vf, another is vfg, and the third is vg. vfg = vg-vf. It's the change in specific volume at a specified pressure when water changes from liquid to vapor.

 

[craglyboy]

yeah Vf is tiny now I have found it got work done to -277.9KJ.

for U1 I got 1670.4KJ from using the formula u=uf+x(ug-uf) and for u2 i thought because i know the specific volume look it up in the steam tables it comes to 2734KJ but I don't get the right answer for heat supplied.

Because it is a isobaric process I used Q=(u2+pv2)-(u1+pv1) but getting no where near the answer so I must of done something wrong.

 

[LawrenceC]

OK, I'll check values from my columns and supply them to you. Then you can decide for yourself whether using vf is worthwhile.

My system is in SAE units.

at 14.696 psi vf= 0.01672; vfg=26.811; vg=26.828

Units are ft^3/lb

So forgetting about vf only creates a very small error.

 

[craglyboy]

yeah Vf is tiny now I have found it got work done to -277.9KJ.

for U1 I got 1670.4KJ from using the formula u=uf+x(ug-uf) and for u2 i thought because i know the specific volume look it up in the steam tables it comes to 2734KJ but I don't get the right answer for heat supplied.

Because it is a isobaric process I used Q=(u2+pv2)-(u1+pv1) but getting no where near the answer so I must of done something wrong.

thanks man can you see where i am being an idiot here, is it just for U2 I can't use that value because its not a pure dry mixture.

 

[LawrenceC]

You can determine whether it is superheated by computing v2. Recall, it was .6 quality before heating at constant pressure. You know the volume, the pressure, and how many kg you have. See where that value of v falls in the steam tables. From that value, you can interpolate to get u2.

 

[craglyboy]

I got the values of U right I was just being an idiot and forgot the values were specific values and forgot factor in that I had 2kg of mass not 1. So I have got the right answer finally!

Thankyou Lawrence C you have been extremely helpful!