Isobaric process. Find magnitude of heat transfer

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SUMMARY

The discussion centers on calculating the magnitude of heat transfer in an isobaric process involving a cylinder filled with steam at a pressure of 350 kN/m² and an initial volume of 0.05 m³. The user initially calculated the heat transfer (dQ) as 575 kJ, using the formula dQ = dU + P(V2 - V1). However, the error identified was in the volume change calculation and the interpretation of the problem, which states that the internal energy increase of 50 kJ applies to each cylinder. Correcting the volume change is crucial for accurate heat transfer calculation.

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tigertan
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Hi there,

I'm having a great deal of trouble with this thermodynamics question.

Cylinder filled with steam at 350 kN/m2. Initial volume is 0.05 m3. Sufficient heat transfer is effected to raise the internal energy in each cylinder by 50 kJ. The piston is moved slowly to maintain the pressure constant. Piston is of area of 0.1 m2, and the piston travels 0.15 m. Find the magnitude of the heat transfer.

So my attempt at the question:

dQ = dH (for isobaric case)
therefore:
dQ = dU + P (V2-V1)

and therefore
dQ = 50kJ + 350(1.55-0.05)
=575 kJ


What am I doing wrong? What am I missing?
 
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tigertan said:
Hi there,

I'm having a great deal of trouble with this thermodynamics question.

Cylinder filled with steam at 350 kN/m2. Initial volume is 0.05 m3. Sufficient heat transfer is effected to raise the internal energy in each cylinder by 50 kJ. The piston is moved slowly to maintain the pressure constant. Piston is of area of 0.1 m2, and the piston travels 0.15 m. Find the magnitude of the heat transfer.

So my attempt at the question:

dQ = dH (for isobaric case)
therefore:
dQ = dU + P (V2-V1)

and therefore
dQ = 50kJ + 350(1.55-0.05)
=575 kJ


What am I doing wrong? What am I missing?

You miscalculated the volume change.
 
Also, there appears to be only one cylinder but the problem says that the Q increases ΔU by 50KJ for EACH cylinder.

AM
 
Last edited:

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