Thermodynamics (please state working)

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Homework Help Overview

The discussion revolves around a thermodynamics problem involving a model Stirling engine that operates between two temperature reservoirs. Participants are exploring how to calculate the heat transferred to the gas from the high temperature reservoir during each cycle, given specific parameters such as the amount of gas, temperatures, and work done by the engine.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of heat transfer during the high temperature process and question the applicability of certain formulas, such as the relationship between internal energy, heat, and work. There is confusion regarding the work done during the isothermal expansion and how it relates to the total cycle.

Discussion Status

The discussion is active, with participants offering different perspectives on how to approach the problem. Some suggest focusing on the specific isothermal process to determine the heat transfer, while others express uncertainty about the correct values and formulas to use. There is no explicit consensus, but several productive lines of inquiry are being explored.

Contextual Notes

Participants note the importance of using the correct temperature scale (Kelvin vs. Celsius) and the distinction between the work done during the entire cycle versus the work done during the isothermal process. There is also mention of the cyclic nature of the process affecting internal energy considerations.

hod032
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Answers are there- but explanation of working out questions would be great.

A model Stirling engine uses n=7.16*10^-3 mol of gas (assumed to be ideal) as a working substance. It operates between a high temperature reservoir at T(H)=93.0 degrees Celsius and a low temperature reservoir at T(C)=23.0 degrees Celius. The volume of its working substance doubles during each expansion stroke. It runs at a rate of 0.8 cycles per second. Assume the engine is ideal.

(i) how much heat is transferred to the gas from the high temperature reservoir during each cycle? (ans - 15.1J)

I've already worked out that the work done by the engine per cycle is -2.89J; and the power of the engine is 2.31W (if that helps)
 
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Well, think of it this way... The heat being transferred from the high temp reservoir only happens during the high temp process. They aren't asking for the total heat transferred for the whole cycle.
 
nickjer said:
Well, think of it this way... The heat being transferred from the high temp reservoir only happens during the high temp process. They aren't asking for the total heat transferred for the whole cycle.

So, do we need to use the formula [tex]\Delta E_{int}=Q+W[/tex] to find the heat transferred to the gas from the high temperature reservoir during each cycle?

The problem is I can't use this formula because the internal energy [tex]\Delta E_{int}[/tex], is not given to us! So how can I find the amount of energy Q?

Edit: I also know that [tex]W_{eng}=Q_{net}=| Q_h | - | Q_c |[/tex] but I still don't know how to obtain Qh and Qc...
 
Last edited:
The heat transferred during the high temp part is just an isothermal expansion. So what is the work done during an isothermal expansion? Since the temperature is constant, the internal energy will not change, so then you will have:

[tex]Q=-W[/tex]

And you will have your heat transfer.
 
nickjer said:
The heat transferred during the high temp part is just an isothermal expansion. So what is the work done during an isothermal expansion? Since the temperature is constant, the internal energy will not change, so then you will have:

[tex]Q=-W[/tex]

And you will have your heat transfer.

I'm a little bit confused here :confused:

The question asks "how much heat is transferred to the gas from the high temperature reservoir during each cycle?". So the question asks for the value of Q, right?

Yes, I know that in an isothermal process the energy transfer Q must be equal to the negative of the work done on the gas [tex]Q=-W[/tex]. Since we already know that the work done by the engine per cycle is -2.89J, Q will be

Q=-(-2.89)=2.89

But this is wrong since the correct answer has to be 15.1J. :confused:
 
The whole cycle isn't one giant isothermal expansion, so you can't say the internal energy is constant through out the whole cycle. Only when heat is being transferred from the high temp reservoir do we care about work and heat flow. That means we only want the work done by the system during this specific part of the cycle.

So the work done by the engine for the full cycle won't help us. You will need to compute the work done by the system just during this isothermal process when it is in contact with the high temp reservoir.
 
nickjer said:
The whole cycle isn't one giant isothermal expansion, so you can't say the internal energy is constant through out the whole cycle. Only when heat is being transferred from the high temp reservoir do we care about work and heat flow. That means we only want the work done by the system during this specific part of the cycle.

So the work done by the engine for the full cycle won't help us. You will need to compute the work done by the system just during this isothermal process when it is in contact with the high temp reservoir.

I see. The internal energy is not constant but I know it equals zero, since it is a cyclic process (i.e. starts and ends at the same state).

So we want to find the value for Qh (energy taken in from a hot reservoir). But I don't know how to obtain it from the formula:

[tex]W=|Q_h|-|Q_c|[/tex]

What value do I substitute for Qc?

Furthermore I don't know how to find the work done by the engine during the isothermal process. In my previous post I used the formula W=-Q but apparently it is wrong...
 
[tex]Q_h[/tex] is just the work done during the isothermal process. And your previous post was wrong because you had the wrong work. Again, the work during the isothermal process is not the work done for the whole cycle. Find only the work done during the isothermal process and you will have the answer.
 
nickjer said:
[tex]Q_h[/tex] is just the work done during the isothermal process. And your previous post was wrong because you had the wrong work. Again, the work during the isothermal process is not the work done for the whole cycle. Find only the work done during the isothermal process and you will have the answer.

What formula should I use??

I'm frustrated because I tried the following to find the work done during the isothermal process only, but again my answer is wrong:

[tex]W=nRT ln \left( \frac{V_i}{V_f} \right)[/tex]

[tex](7.16 \times 10^{-3})(8.314) (93) ln \left( \frac{1}{2} \right)=-3.83[/tex]

[tex]Q=-W=3.83[/tex]
 
  • #10
You have the wrong temperature. You should use Kelvin and not Celsius.
 

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