Thermodynamics Question Calculating change in temperature

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The discussion centers on calculating the change in temperature for an ideal gas undergoing a process where both pressure and volume double. The user initially attempted to use the equation PV=nRΔT but encountered difficulties, leading to confusion about the correct application of the ideal gas law. It was clarified that the correct equation is PV=nRT, not PV=nRΔT, and the user was guided to calculate both initial and final temperatures using this law. The final answer for the change in temperature is stated to be 720K. The conversation emphasizes the importance of correctly applying thermodynamic equations in problem-solving.
Gaith
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Homework Statement

[/B]
50 moles of an ideal gas for which Cp= 5/2R and Cv=3/2R initially has a pressure of 1x10^5 Pa, and a volume of 1.0m^3. It undergoes a process where the pressure and volume both double while they stay proporitional to each other: P=constV. What is the change in temperature for this process?

Homework Equations


ΔU= Q-W
PV=nRΔT
ΔU= nCv(ΔT) [/B]

The Attempt at a Solution


So I started by trying to use PV=nRΔT and calculating T, however I wasnt successful. The answer in my book is in Kelvins, so I tried converting the temperature that I calculated to Kelvins, however it was still wrong.

I'm thinking that I might need to take the integral: ∫ PVdv but I am not sure if that's correct either.

Can somone please help me out, It would be greatly appreciated.

The correct answer is: 720K
 
Last edited:
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Hello.
Gaith said:
PV=NRΔT

The above equation is not correct. The ideal gas law is PV = nRT, not PV = nRΔT.

From PV = nRT can you calculate the initial temperature? How about the final temperature?
 
From the ideal gas law, what is the initial temperature? From the ideal gas law, what is the final temperature?

Chet
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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