Thermodynamics resistance proof

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Homework Help Overview

The discussion revolves around proving that thermal resistance is additive in series, specifically in the context of two slabs in thermal contact. The original poster presents an equation involving thermal resistance and attempts to manipulate it to isolate the total resistance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore energy balance concepts and steady-state conditions. The original poster questions how to eliminate certain variables from their equation. Others suggest equating heat currents and provide alternative approaches to the problem.

Discussion Status

Participants are actively engaging with the problem, offering different perspectives and methods. Some guidance has been provided, particularly regarding the application of steady-state conditions and energy balance, but no consensus has been reached on a single approach.

Contextual Notes

There is an emphasis on understanding the conditions under which the equations apply, particularly regarding dynamic thermal equilibrium and steady-state assumptions.

skirmidirmi
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Homework Statement


Prove that thermal resistance is additive in series

Homework Equations


H=A(TH-Tc)/R
where R=L/k

The Attempt at a Solution



For two slabs in thermal contact where TC is the outside cold temperature and TH is the outside hot temperature

A(TH-Tc)/R=A(TH-T)/R1+A(T-Tc)/R2)

The A's cancel out, and after a bit of math, I've gotten the equation down to

R=(R1+R2)(TH-TC)/(R2(TH-T)+R1(T-Tc)

How can I get rid of the T's with no subscript and just be left with R1+R2 on the right side?
 
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Try considering an energy balance at the point between the two slabs.
 
Are you suggesting that these slabs are in dynamic thermal equilibrium? If so, are you suggesting that I simply equate the two heat currents? I will not have "R" involved in my expression then, only R1 and R2...
I truly want to understand this. Thank you.
 
Yes, the equation applies to steady state conditions only.
 
I'd approach it more simply.

Heat Flow = ΔT/R

So R*Heat Flow = ΔT

The heat flow of R1 is then R1*H = ΔT = (Ti - T1)

And through R2 is R2*H = (T1 - T2)

Heat flow for the system then is

R1*H + R2*H = (Ti - T1) + (T1 - T2) = Ti - T2

If Rtotal*H for the system is Ti - T2, then Rtotal is (R1 + R2)
 
Thank you very much! That is a lot more straightforward than how I was trying to prove it.
 

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