Thermodynamics - reversible isothermal cycle

[Feodalherren]

Homework Statement

Homework Equations

The Attempt at a Solution

I can do everything else except work for part one going from A to B.

What I did was

-∫PdV = -nRT ∫(1/v)dV = -nRT ln (Vf/Vi)

I can solve for T because everything is given, T in Kelvin is 882.
From PV=nRT
T=(5atm)(10L)/1mol*R = 882K

where R = .0820582

Therefore w= -1mol * R * 882 * ln (5) = - 11.8kJ

where R = 8.314

But this is incorrect. It is supposed to be -8.15kJ

 

[ehild]

The Attempt at a Solution

I can do everything else except work for part one going from A to B.

What I did was

-∫PdV = -nRT ∫(1/v)dV = -nRT ln (Vf/Vi)

I can solve for T because everything is given, T in Kelvin is 882.
From PV=nRT
T=(5atm)(10L)/(1mol*R) = 882K

where R = .0820582

Redo the calculation in red.

ehild

 

[Feodalherren]

Hmm...

50 / (.0820582) = 609 K

Argh nevermind I thought it gave me the T in celsius! Thank you Ehild!