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## Homework Statement

A system containing 10kg of water undergoes a reversible isothermal process. The initial state can be characterized as saturated vapor at 300°C. The pressure in the final state is 1MPa. The heat transfer during the process in (inKJ)

## Homework Equations

Q = m(U2-U1)+W

W = PdV

v1 = V/m

v1 = specific volume at initial state

V = volume

## The Attempt at a Solution

The specific volume values were found using the thermodynamic tables for water. I figured that since it was an isothermal process and would be adiabatic. I wanted somebody to see if my answer is correct.

v1=.02167

v2=.25794

V1= 2.5795

V2=2.5794

mass=1.91

T1 =T2 =300°C

Q = mCvo(T2-T1)+W

Q = .717(300-300)+PdV

Q = 0 +1000(2.5794-.2167)

Q = 2362.7