Thermodynamics: ΔE vs ΔU - Uncover the Difference

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The discussion clarifies the distinction between ΔE (total energy change) and ΔU (internal energy change) in thermodynamics. ΔE is defined as ΔE = ΔU + ΔKE + ΔPE, where ΔKE and ΔPE represent changes in macroscopic kinetic and potential energy, respectively. In contrast, ΔU is expressed as ΔU = Q - W, which accounts for heat added to the system (Q) minus work done by the system (W). The key takeaway is that ΔE encompasses both internal and macroscopic energy changes, while ΔU focuses solely on internal energy.

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thinkcentre12
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My question is what is the difference between ΔE and ΔU. Because I see both equations 2 and 3 interchangeably . But then I see equation 1. So there has to be a difference between them since they are using both symbols in one equation. I thought U was internal energy while E was total energy. So I am confused to what the difference is between 2 and 3 why can I use either equation?

Thanks I tried to explain my thinking

ΔE = ΔU + ΔKE + Δ PE (1)

ΔE = Q - W (2)

ΔU = Q - W (3)
 
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thinkcentre12 said:
My question is what is the difference between ΔE and ΔU. Because I see both equations 2 and 3 interchangeably . But then I see equation 1. So there has to be a difference between them since they are using both symbols in one equation. I thought U was internal energy while E was total energy. So I am confused to what the difference is between 2 and 3 why can I use either equation?

Thanks I tried to explain my thinking

ΔE = ΔU + ΔKE + Δ PE (1)

ΔE = Q - W (2)

ΔU = Q - W (3)
E is the symbol for the total energy of the system and U is the symbol for internal energy of the system.

E takes into account the macroscopic KE and PE of the system as well as the internal energy, U. The macroscopic kinetic energy and potential energy of the system are due to the motion and position of the centre of mass of the system. U can be thought of as the microscopic KE and PE - the kinetic and potential energies of all the constituent molecules in the system measured relative to the centre of mass of the system.

Your equation (2) is correct only if the macroscopic KE and PE do not change.

AM
 
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