Thermodynamics-using ideal gas table

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SUMMARY

This discussion focuses on solving thermodynamic problems using the ideal gas model and specific heat tables. The problems involve calculating the change in specific entropy for various gases under different conditions, using both ideal gas tables (specifically Table A22 from "Fundamentals of Thermodynamics, Edition 5") and constant specific heat values from Table A20. The correct answers for the problems were confirmed through interpolation and the application of the formula Δs = cp ln(T2/T1) - R ln(P2/P1), where R is the difference between specific heats cp and cv. The user successfully solved part A but encountered challenges with part B due to the lack of clarity on whether the process was at constant volume or pressure.

PREREQUISITES
  • Understanding of the ideal gas law and its applications
  • Familiarity with specific heat capacities (cp and cv)
  • Knowledge of entropy and its significance in thermodynamics
  • Ability to interpolate data from thermodynamic tables
NEXT STEPS
  • Study the derivation and application of the entropy change formula Δs = cp ln(T2/T1) - R ln(P2/P1)
  • Learn how to use ideal gas tables, specifically Table A22 and Table A20
  • Research the implications of constant pressure vs. constant volume processes in thermodynamics
  • Practice additional problems involving entropy calculations for various gases
USEFUL FOR

Students and professionals in mechanical engineering, chemical engineering, and physics who are studying thermodynamics and need to understand the application of ideal gas tables and specific heat calculations.

alberto23
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thermodynamics--using ideal gas table

problem says:

6.25 employing the ideal gas model, determine the change in specific entropy between the indicated states, in kJ/kg K. Solve 2 ways: use the appropriate ideal gas table, and a constant specific heat from Table A-20.

(a) air, p1 = 100 kPa, T1 = 20°C → p2 = 100 kPa, T2 = 100°C
(b) air, p1 = 1 bar, T1 = 27°C → p2 = 3 bar, T2 = 377°C
(c) carbon dioxide, p1 = 150 kPa, T1 = 30°C, p2 = 300 kPa, T2 = 300°C
(d) carbon monoxide, T1 = 300K, v1 = 1.1 m3/kg → T2 = 500K, v2 = 0.75 m3/kg
(e) nitrogen, p1 = 2 Mpa, T1 = 800K → p2 = 1 Mpa, T2 = 300K

answers are:
A) 0.24289, 0.2431
B) 0.47632, 0.47684
C) 0.4769, 0.4862
D) 0.2701, 0.2696
E) -0.8373, -0.8389

i did part A fine and got the right asnwer. solving using the first method (appropriate ideal gas table)--which is table A22 in my book (fundamentals of thermodynamics edition 5). you just have to convert temp to kelvin and match it up with the corresponding "s" value. the exact values aren't on table so i had to interpolate. then i did s2-s1 and got the right answer. solving using the second method (Table A20--"ideal gas specific heats of some common gasses"), i used the temperatures to find the cp values. then i averaged the 2 cp values together and used the formula (delta)s=cp*ln(T2/T1). this gave me the right answer.


but...for part B, it is not constant pressure and it doesn't say if its constant volume or not, so i don't know how to use the specific heat table for this.

if you can help me...thanks.
 
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\Delta s\, =\, c_p\, ln\, \frac{T_2}{T_1}\, -\, R\, ln\, \frac{P_2}{P_1}

remembering R = c_p - c_v
 
astronuc, thanks for the help. i found that formula in my book burried in a page of derivations. I'm pretty sure its the right one because my answers were very very close to the ones given. thanks!
 

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