An ordinary glass is filled to the brim with 360.0 mL of water at 100°C. If the temperature decreased to 18°C, how much water could be added to the glass? Volume Expansion Coefficient for Water ß (C°)^-1 (I believe then, that I use Celsius and not Kelvin?) ß(water) = 210E-6 ß(glass) = 9E-6 Vo = 360 mL ⌂T = -82°C (= -355°K) (or is it positive, since change is the absolute value of it?) V = Vo(1+ß⌂T) V = 360(1+210E-6*-82) V = 360 - 360*210E-6*-82 V = 360 - 6.199 Interpreting this, I thought that there would be 6.2 mL more room for water (unless water increases in volume as it is cooled?) For the container, V = 360(1+9E-6*-82) V = 360 - .2657 So .2657 mL more room in the container. Adding 6.2 + .2657 = 6.47 mL I don't know whether this is right or wrong, and had a few similar attempts that were wrong, so am I correct in my thinking? Also, I know that water is the only thing that contracts when heated and expands when cooled, but I didn't think this would make sense, since it would just be overflowing, when the question seems to imply that it is leaving room for more water.