Theta_max = 53.8° Acceleration of Hoop on Inclined Ramp

Click For Summary
SUMMARY

The discussion focuses on the dynamics of a circular hoop rolling down an inclined ramp. The acceleration of the hoop's center is correctly expressed as (g/2)*sin(theta), where g is the acceleration due to gravity and theta is the incline angle. The minimum coefficient of friction required for the hoop to roll without slipping is determined to be 1/2*tan(theta). For the maximum angle theta_max that allows the hoop to roll without skidding, participants clarify that it is the inverse of the minimum coefficient of friction derived in Part B.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with rotational dynamics and rolling motion
  • Knowledge of trigonometric functions, specifically sine and tangent
  • Basic grasp of friction concepts, particularly static friction
NEXT STEPS
  • Study the principles of rotational motion and moment of inertia
  • Learn about the relationship between friction and rolling motion
  • Explore the derivation of equations of motion for rolling objects
  • Investigate the effects of incline angles on rolling dynamics
USEFUL FOR

Students of physics, mechanical engineers, and anyone interested in the mechanics of rolling objects on inclined surfaces.

cmcc3119
Messages
16
Reaction score
2
A circular hoop of mass m, radius r, and infinitesimal thickness rolls without slipping down a ramp inclined at an angle theta with the horizontal. View Figure

PART A. What is the acceleration of the center of the hoop?

Express the acceleration in terms of physical constants and all or some of the given quantities: m,r and theta.
= (g/2)*sin(theta)

IS THIS CORRECT? It is the answer I got but I could not see any reason to have r and m in the final equation. I am scared to enter it as the computer might say it is wrong like this!



PART B. What is the minimum coefficient of friction needed for the hoop to roll without slipping?

Express the minimum coefficient of friction in terms of all or some of the given quantities: m, r, and theta
= 1/2*tan(theta)

IS THIS CORRECT? Again as above this is the answer I got but I could not see any reason to have r and m in the final equation. I am scared to enter it as the computer might say it is wrong like this!



PART C: Imagine that the above hoop is a tire. The coefficient of static friction between rubber and concrete is typically at least 0.9. What is the maximum angle theta_max you could ride down without worrying about skidding?
Express your answer numerically, in degrees, to two significant figures.

I am confused as it is asking for the maximum angle. Does that mean I still use the minimum coefficient. Can someone please start me off as I think my answers to the other two are correct but this one I am hesitant on.

Thank you lovely intelligent people!
 

Attachments

  • HOOP.jpg
    HOOP.jpg
    4.9 KB · Views: 1,067
Physics news on Phys.org
Parts A and B are correct. But next time show your work, don't just give an answer. Part C is just the inverse of part B. For any given angle, you know the minimum coefficient required; just work it in reverse.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
Replies
11
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 18 ·
Replies
18
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K