Triopas
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Ahhh! Thank you! I was able to transpose that equation for VTh and ended up with the answer I was expecting.
Thanks again.
Thanks again.
The discussion focuses on applying Thévenin's theorem to determine the load current in a circuit with a 50 Ω load connected to two voltage sources and their associated reactances. Key methods discussed include converting the load to a complex impedance, calculating the Thévenin equivalent voltage, and using nodal analysis for voltage calculations. Participants emphasized the importance of separating components and using complex arithmetic to solve for the load current accurately.
PREREQUISITESElectrical engineering students, circuit designers, and anyone involved in analyzing AC circuits using Thévenin's theorem and complex impedance methods.
I think you mean current source. You added the two Norton sources.Spongecake said:I am currently on part c) and have converted each voltage source and series impedance into a current source and parallel impedance using Ohms Law, I = V/Z which i get 103.75 for v1 and -J69.17 for v2.
Then combining them to get 103.75-j69.17 as my voltage source.
Yes, you're on the right track.Then to combine J4 and J6 which are in parallel which i make j2.4.
The next bit I'm slightly confused on which is to use current divider rule to calculate the load current which i think is Ix=[Rt/(Rt+Rx)]*It
It= the current source. Please can advise me if I'm on the right track.