Thevenin's Theorem: Solving Homework Statement on Load Current

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SUMMARY

The discussion focuses on applying Thévenin's theorem to determine the load current in a circuit with a 50 Ω load connected to two voltage sources and their associated reactances. Key methods discussed include converting the load to a complex impedance, calculating the Thévenin equivalent voltage, and using nodal analysis for voltage calculations. Participants emphasized the importance of separating components and using complex arithmetic to solve for the load current accurately.

PREREQUISITES
  • Understanding of Thévenin's theorem and its application in circuit analysis.
  • Familiarity with complex impedance and phasor representation.
  • Knowledge of nodal analysis for circuit voltage calculations.
  • Ability to perform complex arithmetic operations.
NEXT STEPS
  • Learn how to calculate Thévenin equivalent circuits in various configurations.
  • Study complex impedance calculations, including converting between polar and rectangular forms.
  • Explore nodal analysis techniques for solving circuit problems.
  • Investigate the implications of phase angles in AC circuit analysis.
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing AC circuits using Thévenin's theorem and complex impedance methods.

  • #181
Ahhh! Thank you! I was able to transpose that equation for VTh and ended up with the answer I was expecting.

Thanks again.
 
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  • #182
I am currently on part c) and have converted each voltage source and series impedance into a current source and parallel impedance using Ohms Law, I = V/Z which i get 103.75 for v1 and -J69.17 for v2.
Then combining them to get 103.75-j69.17 as my voltage source.
Then to combine J4 and J6 which are in parallel which i make j2.4.

The next bit I'm slightly confused on which is to use current divider rule to calculate the load current which i think is Ix=[Rt/(Rt+Rx)]*It
It= the current source. Please can advise me if I'm on the right track.
 
  • #183
Spongecake said:
I am currently on part c) and have converted each voltage source and series impedance into a current source and parallel impedance using Ohms Law, I = V/Z which i get 103.75 for v1 and -J69.17 for v2.
Then combining them to get 103.75-j69.17 as my voltage source.
I think you mean current source. You added the two Norton sources.
Then to combine J4 and J6 which are in parallel which i make j2.4.

The next bit I'm slightly confused on which is to use current divider rule to calculate the load current which i think is Ix=[Rt/(Rt+Rx)]*It
It= the current source. Please can advise me if I'm on the right track.
Yes, you're on the right track.
 
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  • #184
Hello

I've been struggling with this question for a good three months now. I have read through this whole thread, been into see my tutor (distance learning so contact isn't regular) and got books out from the university library.

And I still don't have the slightest clue with where to even start. Not even a little bit. I have tried to go to other questions on the assignment but there's no luck there either. The course material I'm assuming is similar to that of the others posting on here as it's almost useless.

Attached is all I have so far.

Adam
 

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