Thin Cylinder Theory: Determining Torsional Shear Stress

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SUMMARY

The discussion focuses on calculating torsional shear stress in a copper cylinder subjected to combined loading, specifically pressure and torque, using thin cylinder theory. The maximum shear stress due to pressure is given by the equation τmax = pr/4t, where p is the pressure in psi, r is the outer radius in inches, and t is the wall thickness in inches. The normal stress from pressure is calculated as σ = pr/t, while the shear stress from torque is τ = Tc/J, where T is the applied torque in in·lbf, c is the outer radius in inches, and J is the polar moment of inertia in in4. Combining these stresses and applying Mohr's Circle allows for the determination of principal stresses.

PREREQUISITES
  • Understanding of thin cylinder theory
  • Familiarity with Mohr's Circle for stress analysis
  • Knowledge of shear and normal stress equations
  • Basic mechanics of materials principles
NEXT STEPS
  • Study the application of Mohr's Circle in combined loading scenarios
  • Learn about polar moment of inertia calculations for different shapes
  • Explore the effects of varying wall thickness on stress distribution in cylinders
  • Investigate material properties of copper relevant to torsional stress analysis
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Mechanical engineers, materials scientists, and students studying mechanics of materials who are involved in stress analysis of cylindrical structures under combined loading conditions.

brd
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Can anyone tell me what equation I need to use to determine the torsional shear stress using the thin cylinder theory to a copper cylinder which is under pressure and a twisting force (torque).
 
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You have a combined loading scenario.

The pressure will create a normal stress. However, when you do a Mohr's circle on the pressure alone, you will develop a shear stress on your location rotated 45° in plane. From the pressure alone, Mohr's theory will show you that the max shear is \tau_{max} = \frac{pr}{4t} where:
p = pressure in psi
r = outer radius in in.
t = wall thickness in in.

The normal stress resulting from the pressure is \sigma = \frac{pr}{t}.

The shear stress due solely to the torque applied will be
\tau = \frac{T*c}{J} where:
T = applied torque in in*lbf
c = outer radius in in.
J = polar moment of inertia in in^4

You'll have to combine the stresses in the same directions and do a Mohr's Circle on the total load to determine the principle stresses.
 

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