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yes, understood , this is for steady flow right?

- Thread starter Rahulx084
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yes, understood , this is for steady flow right?

Mentor

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Yes. So now what do you get if you divide the equation by ##2\pi r \delta r \delta z## and then take the limit as ##\delta r## and ##\delta z## approach zero?yes, understood , this is for steady flow right?

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##\frac 1 r## ##\frac {dr\tau_{rz}} {dr}## + ##\frac {dp} {dz}## , this is what I'm getting sir .

Mentor

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Excellent. So now you have some actual experience at applying the Cauchy Stress Relationship to a problem. Does that help answering your questions?##\frac 1 r## ##\frac {dr\tau_{rz}} {dr}## + ##\frac {dp} {dz}## , this is what I'm getting sir .

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Mentor

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The term in #19 follows from the equations for the stress tensor components for a viscous Newtonian fluid. Are you familiar with these equations?

When you have a cubical element (or rectangular parallelepiped), you use the stress tensor in component form for Cartesian coordinates.

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Mentor

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See page 29 of http://web.mit.edu/2.25/www/pdf/viscous_flow_eqn.pdf

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Mentor

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See Eqns. 43 of that same reference.

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