This equation is NOT exact, correct?

[darryw]

Homework Statement

(2y^2 - 4x + 5) dx = (4-2y+4xy)dy

i divided by dx and rearranged...

(-2y^2 + 4x - 5) + (4-2y+4xy)dy/dx
this is M....and this is N

then took partial derivatives...

M_y = -4y

N_x = 4y

M_y not equal to N_x, therefore not exact..

but it is so close that i suspect i am making some mistake..

??

Homework Equations

The Attempt at a Solution

 

[Mark44]

Correct, it's not exact. Be careful, though - you started with an equation and lost the = in your next line.

Here's a better rearrangement.

(2y^2 - 4x + 5) dx + (-4 + 2y - 4xy)dy = 0
(...M...)...(...N...)

 

[darryw]

thANKS.. shouldve been..
(-2y^2 + 4x - 5) + (4-2y+4xy)dy/dX = 0