This is about power dissipation.

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raoulduke1
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i got part (a) by using the equation Vab + E - Ir
Which gives 26.57V (also the current = 1.171A)
Having trouble getting the power dissipated, any ideas?
 

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raoulduke1 said:
i got part (a) by using the equation Vab + E - Ir
Which gives 26.57V (also the current = 1.171A)
Having trouble getting the power dissipated, any ideas?

Welcome to the PF.

You just have a current divider with those two parallel resistors. Find the voltage across the parallel combination of those two resistors, and use that voltage independently to calculate the power dissipated in each resistor.
 
Thanks man, its good be here!