Three concentric shells, one uncharged (Potential)

Click For Summary
SUMMARY

The discussion focuses on calculating the charge on the middle shell of three concentric shells, given the potential of the middle shell at 1 kV. Participants emphasize the importance of using Gauss' theorem to analyze the electric fields E1, E2, and E3 between the shells. The correct approach involves integrating the electric fields to determine the potential difference, specifically from points c to d and e to infinity. The confusion arises from the incorrect assumption that the electric field inside the middle shell is non-zero, which contradicts the properties of conductors.

PREREQUISITES
  • Understanding of Gauss' theorem in electrostatics
  • Familiarity with electric field and potential concepts
  • Knowledge of integration techniques for electric fields
  • Basic principles of conductors and their electric fields
NEXT STEPS
  • Study the application of Gauss' theorem in electrostatics
  • Learn how to calculate electric potential from electric fields
  • Explore the properties of conductors in electrostatic equilibrium
  • Investigate the relationship between charge, electric field, and potential
USEFUL FOR

Students studying electrostatics, physics educators, and anyone interested in understanding electric fields and potentials in multi-shell systems.

jegues
Messages
1,085
Reaction score
3

Homework Statement



See figure attached.

Homework Equations





The Attempt at a Solution



See figure attached for my attempt.

I'm confused as to how I am supposed to use these 3 electric fields, E1, E2 and E3, as well as the potential of the middle shell, V = 1kV (with reference point at infinity), to calculate the charge on the middle shell, [tex]q_{mid}[/tex]

I know I should be doing some integration over the electric fields in order to get the potential, but it's not obvious to me what path I should take to only have the potential of the middle shell.

The solution gives it as from c to d, and then from e to infinity.

Why so?

Can someone clarify? Is the picture I drew incorrect?

Thanks again!
 

Attachments

  • Q1.77.JPG
    Q1.77.JPG
    40.3 KB · Views: 569
  • AT1.77.JPG
    AT1.77.JPG
    44.6 KB · Views: 529
Physics news on Phys.org
You wrote an expression for the field inside the middle shell which you know can't be right, since the E field inside a conductor is zero.

But you have the right idea in using Gauss' theorem. Use it for the spaces between the shells, and integrate the E fields accordingly to get the potentials. Call the charge on the middle shell Qb for the moment.

Then, you need to compute Qb given the middle shell's potential as 1 kV. Careful how you do this, it isn't just kQb/Rbo where k = 9e9 and Rbo is the outer radius of the middle shell (why not?).
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
1K
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K