(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

You throw a ball straight up @ 22m/s and you catch it 3.6 seconds later. How fast was it going when you caught it?

2. Relevant equations

[tex]v_f=v_i+at[/tex]

3. The attempt at a solution

I found the right solution. But to me, it seems it should be more complex then this.

The ball goes 22m/s second and gravity had its opposition at 9.8 m/s squared going up but going down 22m/s has nothing to do with it falling. So why wouldn't this be 2 equations, one for going up with v_i of 22 and the other for going down with v_i at 0.

The answer of course is 13.28m/s with equation above.

Perhaps this has something to do with a quadratic equation, but I don't know how to see this with the correct perspective.

I did look at this though and am just unsure how to really view this

http://www.wolframalpha.com/input/?i=-9.8x^2+%2B+22x

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# Homework Help: Throwing ball in air and final velocity.

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