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## Main Question or Discussion Point

After i figured out how to show length contraction in this topic. I tried to use a similar way to show time dilation in Minkowski diagram.

According to just said I set up my problem so that frame [itex]x,ct[/itex] is my rest frame as edges of a time interval [itex]\Delta t[/itex] happen on a same vertical line. This means that time interval [itex]\Delta t[/itex]

But when i draw time interval [itex]\Delta t'[/itex] it is obvious that it is shorter than interval [itex]\Delta t[/itex]. So why do

Marks [itex]1'[/itex] and [itex]2'[/itex] on [itex]ct'[/itex] axis are further appart than marks [itex]1[/itex] and [itex]2[/itex] on [itex]ct[/itex] axis (i even draw a parabola to show this). This is why [itex]\Delta t = 1[/itex] and [itex]\Delta t' < 1'[/itex].

http://shrani.si/f/v/F4/2Fo9hrOu/avezo-1.png [Broken]

*Time dilation means that time interval between two events is the shortest in the frame in which those two events happen in same place. We call this frame its rest frame.*According to just said I set up my problem so that frame [itex]x,ct[/itex] is my rest frame as edges of a time interval [itex]\Delta t[/itex] happen on a same vertical line. This means that time interval [itex]\Delta t[/itex]

*should be the shortest time interval compared to time intervals in any other frames*. Including frame [itex]x',ct'[/itex].But when i draw time interval [itex]\Delta t'[/itex] it is obvious that it is shorter than interval [itex]\Delta t[/itex]. So why do

**i get time contraction instead time dilation**?Marks [itex]1'[/itex] and [itex]2'[/itex] on [itex]ct'[/itex] axis are further appart than marks [itex]1[/itex] and [itex]2[/itex] on [itex]ct[/itex] axis (i even draw a parabola to show this). This is why [itex]\Delta t = 1[/itex] and [itex]\Delta t' < 1'[/itex].

http://shrani.si/f/v/F4/2Fo9hrOu/avezo-1.png [Broken]

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