Time for capacitor charging in RLC circuit.

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SUMMARY

The time for a capacitor to charge to 0.63% of the source voltage in a series RLC circuit is determined by the time constant, which can be expressed as 2L/R or as (1/R) * (L/C)^(1/2). The circuit is connected to a battery via a switch, and the behavior of the capacitor voltage can exhibit oscillations based on the values of resistance (R), inductance (L), and capacitance (C). To accurately determine the charging time, one must solve the differential equation governing the charge on the capacitor, considering initial conditions where both charge and current are zero.

PREREQUISITES
  • Understanding of series RLC circuits
  • Knowledge of differential equations
  • Familiarity with time constants in electrical circuits
  • Basic concepts of charge and current in capacitors
NEXT STEPS
  • Study the derivation of the time constant for RLC circuits
  • Learn how to solve differential equations related to capacitor charging
  • Explore the effects of varying R, L, and C on circuit behavior
  • Investigate oscillatory behavior in RLC circuits and its implications
USEFUL FOR

Electrical engineering students, circuit designers, and anyone interested in analyzing the behavior of RLC circuits during capacitor charging.

Rts11
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Homework Statement


In series RLC circuit how much time it takes for capacitor to charge to 0.63% of source voltage..?
time constant is the time taken by a capacitor to charge to 0.63% of source voltage and in rc circuit time constant is RC. but what about for capacitor in series RLC circuit..?

Homework Equations

The Attempt at a Solution


I searched allover the web and Wikipedia but i didn't find anything. i saw a formula saying that time constant is
2L/R and some where i saw time constant as 1/R*(L/C)1/2.but i don't know it is for inductor(L) or capacitor(C) and how to relate it to capacitor voltage.
.
 
Last edited:
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Rts11 said:

Homework Statement


In series RLC circuit how much time it takes for capacitor to charge to 0.63% of source voltage..?

.
Copy the whole text of the original problem, please. Is the RLC circuit connected to a battery by a switch?
 
ehild said:
Copy the whole text of the original problem, please. Is the RLC circuit connected to a battery by a switch?
Yes the RLC circuit is connected to a battery by closing the switch and how much time in takes only the capacitor to get 0.63% of source voltage.
 
Is it 63% of the source voltages or 0.63 %?
There can be oscillations in the circuit, so the voltage across the capacitor can be a given value quite a few times, depending the actual values of R, L, C. Were they given?
You have two solve the differential equation for the charge on the capacitor, taking the initial conditions into account. In this case it is that both the charge and the current (time derivative of the charge) are zero. You get quite a complicated equation.
 

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