Time invariance of Schrodinger equation

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SUMMARY

The Schrödinger equation is linear in time but does not exhibit time invariance, contrasting with other fundamental laws such as Maxwell's and Newton's equations. This lack of time invariance is attributed to the nature of the time reversal operator, which is antiunitary, requiring a complex conjugation of the wave function in addition to a sign change in time. In contrast, the Dirac equation, which employs first-order derivatives, maintains time invariance and respects relativistic principles.

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  • Understanding of the Schrödinger equation and its formulation
  • Familiarity with time reversal symmetry in quantum mechanics
  • Knowledge of the Dirac equation and its implications in relativistic quantum mechanics
  • Basic concepts of linear operators and their properties in physics
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Avijeet
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The Schrödinger equation is linear in time. I was wondering if that means that is not invariant under time reversal. That would be a surprise because all other microscopic laws (Maxwell's equations, Newton's equations) are time invariant.
Can you please clear this doubt?
 
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Avijeet said:
The Schrödinger equation is linear in time. I was wondering if that means that is not invariant under time reversal. That would be a surprise because all other microscopic laws (Maxwell's equations, Newton's equations) are time invariant.
And it does not respect any more the relativistic invariance.
Only the Dirac equation does. It only uses first order derivatives.
 
Actually it is time invariant, since the time reversal operator is not unitary but antiunitary, so you have to complex-conjugate the wave function besides changing the sign of the time.
Of course it doesn't respect relativistic invariance.
 

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