TIme needed for a capacitor to reach a fraction of its final charge

AI Thread Summary
To determine the time for a capacitor to reach 2/3 of its final charge, the equation 2/3Qf = Qf(1-e^-t/RC) is used. By simplifying, it can be shown that e^-t/τ equals 1/3 through basic algebraic manipulation. This involves removing Qf from both sides and rearranging the terms. Additionally, the expression e^-t/τ is always positive because it represents an exponential decay function. Understanding these steps clarifies the process of solving for the time variable in capacitor charging scenarios.
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Homework Statement
how much time elapses for the capicitor to reach 2/3 of its final charge?
Relevant Equations
e^-t/Tau
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I am a little lost on the last step of this problem. I get that we want to know how much time elapses for the capacitor to reach 2/3 of its final charge. That is why 2/3Qf is equal to Qf(1-e^-t/RC).

I don't understand how we make the jump to e^-t/Tau is equal to 1/3? and then somehow e^-t/Tau is positive.

Could someone explain these steps to me?
 
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quittingthecult said:
Homework Statement:: how much time elapses for the capicitor to reach 2/3 of its final charge?
Relevant Equations:: e^-t/Tau

View attachment 291407

I am a little lost on the last step of this problem. I get that we want to know how much time elapses for the capacitor to reach 2/3 of its final charge. That is why 2/3Qf is equal to Qf(1-e^-t/RC).

I don't understand how we make the jump to e^-t/Tau is equal to 1/3? and then somehow e^-t/Tau is positive.

Could someone explain these steps to me?
That step is just a little basic algebra. They left out a couple steps. Start with ##\frac{2}{3} Q_f =Q_f(1-e^{-t/\tau})## and solve for t.
 
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Answering your first question, remove Qf from both sides, and then just rearrange terms. ( I assume that you are familiar with that).
As regards your second question: e^-t/Tau= 1/(e^t/Tau) so it will be always positive.
https://www.wolframalpha.com/input/?i=plot+e^-x
 
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