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**Time period of SHM !**

ellloO ^.^

## Homework Statement

<Q>A particle executes SHM under the restoring force provided by a spring. The time period is T . If the spring is divided in 2 equal parts and one part is used to continue the SHM, The time period will

<A> remain T <b> become T/2 <c> become 2T <d> become T/(2

^{1/2})

## Homework Equations

>If on a particle of mass "m" at a displacement "x" from the mean position , a force " -kx " acts ;then the particle will be in SHM abt that mean position. [ k = constant]

T = [2 [tex]\pi[/tex] (m)

^{1/2}]/(k)

^{1/2}

## The Attempt at a Solution

>>Earlier, the particle was acted upon by force of magnitude "kx" when it was "x" away from mean position and thus time period

T =[2 [tex]\pi[/tex](m)

^{1/2}]/(k)

^{/2}

>>If we use the half part only , still the particle will be acted upon by force of magnitude "kx" and time period T will not change.

>>But the answer is <d> become T/(2

^{1/2})

Little help ^.^

{ lol don't know why the Pie symbol is flying above all other words }