Time taken for free falling objects to travel a set distance

[Jude Caird]

The time taken for a free-falling object to fall a set distance (on earth) is, according to Wikipedia, described by the equation:

t = √(2d/g).

Why is the distance doubled in this equation/ how is this derived?

 

[axmls]

Do you know any of the standard kinematics equations for a constant acceleration?

 

[Jude Caird]

K = 1/2mv²?

 

[PeroK]

K = 1/2mv²?

That's not a good answer!

 

[Jude Caird]

Sorry for my ignorance.

 

[PeroK]

Sorry for my ignorance.

Have you just picked up this formula from Wikipedia without any prior knowledge or are you learning some physics/kinematics?

 

[Jude Caird]

I am interested in orbital mechanics etc. I have a suitable understanding of physics and kinematics and the formulae associated with gravity. I tried to derive the formula from my own knowledge, but failed.

 

[PeroK]

I am interested in orbital mechanics etc. I have a suitable understanding of physics and kinematics and the formulae associated with gravity. I tried to derive the formula from my own knowledge, but failed.

You've never seen the equation $s = \frac{1}{2}at^2$ then?

 

[Jude Caird]

You've never seen the equation $s = \frac{1}{2}at^2$ then?

no

 

[Jude Caird]

You've never seen the equation $s = \frac{1}{2}at^2$ then?

Is that what it's derived from?

 

[PeroK]

Is that what it's derived from?

Yes, you could google for SUVAT or "kinematics". Or, try this:

http://www.examsolutions.net/maths-revision/mechanics/kinematics/suvat/derivation/tutorial-1.php

 

[Jude Caird]

Yes, you could google for SUVAT or "kinematics". Or, try this:

http://www.examsolutions.net/maths-revision/mechanics/kinematics/suvat/derivation/tutorial-1.php

Thank You