Time to travel at relativistic speed

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Homework Help Overview

The discussion revolves around a problem in relativistic travel, specifically calculating the time taken for a spaceship traveling at 0.90 times the speed of light over a distance of 80 light years. Participants are examining different methods for determining the travel time and questioning the validity of the textbook's approach.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate travel time using two methods: one based on a formula from the textbook and another using a direct calculation of distance over speed. Some participants question the logic behind the textbook's method, suggesting it may be incorrect. Others provide alternative reasoning based on the relativistic effects of traveling at high speeds.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and the textbook's explanation. Some guidance has been offered regarding the potential misunderstanding of the textbook's method, but no consensus has been reached on the correct approach.

Contextual Notes

There is mention of a possible error in the textbook's explanation, specifically regarding the calculation of time based on relativistic speeds. Participants are also considering the implications of approximations in mathematical series as they relate to the problem.

jl1642
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I have a relatively simple problem that I'm having trouble with.
A ship is going at 0.90 c, over a distance of 80 light years. In my text the method for determining the time spent traveling is:

80 years + (0.1 * 80) = 88 years
This method seems logical, at 0.9 of the speed of light this trip should take 80 years plus that missing 0.1 of the speed of light.

I tried t = d/v :
t = 80 years / (0.9 light years per year)
t = 88.888889

I'm not sure what is going on, I see no logical error with either approach. Any help is appreciated.
 
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jl1642 said:
80 years + (0.1 * 80) = 88 years
This method seems logical, at 0.9 of the speed of light this trip should take 80 years plus that missing 0.1 of the speed of light.
This does not make sense to me. This was in your textbook?

You are going slower than lightspeed by a factor of 1/.9 = 1.111..., not 1.10. So it should take you 80 years + 0.111...*80 = 88.88...

I tried t = d/v :
t = 80 years / (0.9 light years per year)
t = 88.888889
This makes sense. (Note that it's equivalent to what I said above.)
 
Thanks! I thought I was right, it just messed me up that the textbook was wrong.
 
Did your textbook say it was equal to 88 years or approximately equal to 88 years?

Recall the sum of a geometric series:

1+x+x^2+\hdots = \frac{1}{1-x}

If x is small, you can use the approximation

\frac{1}{1-x}\cong 1+x

where you truncate the series after one term without introducing much error. That may be what your book was doing. If it says the time was exactly 88 years, though, it's wrong.
 
No, the textbook introduces the method with an example question, exactly as I wrote above, with 80 + (0.1*80).
 

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