Tipping Point of Stationary Barbell

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SUMMARY

The discussion centers on a physics problem involving a uniform bar of length 2200mm supported at two points, 1190mm apart, with sections A and C each measuring 445mm. The total mass of the bar is 20kg, and a load of width 67mm is placed in the middle of Section C. The objective is to determine the mass x that causes the bar to tip, expressed in terms of the mass of Section A or C. Participants emphasize the importance of showing prior calculations and understanding the problem's parameters to receive assistance.

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  • Understanding of static equilibrium and tipping points
  • Knowledge of center of mass calculations
  • Familiarity with basic physics principles related to levers
  • Ability to interpret and analyze physical problems involving forces and moments
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of tipping points and static equilibrium in physical systems.

vedant_krish
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New user has been reminded to always show their work when posting schoolwork questions
TL;DR Summary: Please Help. I need an answer for an Investigation

if a uniform bar of length 2200mm is supported evenly on 2 points (1 and 2) 1190mm apart. The bar is comprised of 3 sections (A, B and C) of varying masses. Section A and C have equal mass and volume and is comprised of the parts of the bar hanging before Point 1 and extending past Point 2 respectively. The length of Section A and C are both 445mm. The total mass of the bar is 20kg. A Load of width 67mm and x kilogram mass is placed in the middle of Section C. For what value x does the bar start tipping? (Answer in terms of Mass of Section A or C)

Mentor note: Moved to homework forum, so no template.
 
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Welcome, @vedant_krish !

What calculations have you done to reach that needed answer?
What are you investigating?

Also, where the length of sections A and C (445 mm) is measured from?

2200 mm - 1190 mm ≠ 2 x 445 mm
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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