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## Main Question or Discussion Point

The example I am looking at in my text book starts by considering and area of the rotor surface of width w and length L.

Then the axial current flowing in the width w is equal to I=w

So from the Lorentz force F=I

F= w

so the force per unit area is F/wL which becomes:

F=

Then to obtain the torque the force per area is multiplied by the entire area of the rotor (2∏rL) then multplied by the radius of the rotor

So the overall torque equation becomes:

T=

What doesn't make sense is how can the current be equal to wA? by the Lorentz equation the force on a current carrying conductor is I

Regards

Dan

Then the axial current flowing in the width w is equal to I=w

__A__which is exposed to a radial flux density__B__So from the Lorentz force F=I

__B__x__L__the equation becomesF= w

__A____B__x__L__so the force per unit area is F/wL which becomes:

F=

__B____A__Then to obtain the torque the force per area is multiplied by the entire area of the rotor (2∏rL) then multplied by the radius of the rotor

So the overall torque equation becomes:

T=

__B____A__x 2∏rL x rWhat doesn't make sense is how can the current be equal to wA? by the Lorentz equation the force on a current carrying conductor is I

__B__x__L__so the width and area of the conductor carrying the current I does not matter? so why does it apply here?Regards

Dan