Torque Help -- Tension in a Hoist Cable

  • Thread starter smr101
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Hi, I'm having a problem with 3. (b) (ii) here.

I know that the frictional torque is 1500Nm and that from (b)(i) being 5055N I assume this is multiplied by 1.5M (drum shaft radius) which gives me 7582.5N. Do I have to calculate the angular acceleration of the drum from here, which could then give me the torque? And if so, how?

Help much appreciated. Answer and solution below.

9fVTB.jpg

1dUdy.jpg
 

Answers and Replies

  • #2
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In addition to this how is the power calculated for (b)(iii)? I understand it is two times the torque but why?

Thanks.
 
  • #3
CWatters
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Two times the torque?

Power = Torque * angular velocity
 
  • #4
CWatters
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Hi, I'm having a problem with 3. (b) (ii) here.
I know that the frictional torque is 1500Nm and that from (b)(i) being 5055N I assume this is multiplied by 1.5M (drum shaft radius) which gives me 7582.5N. Do I have to calculate the angular acceleration of the drum from here, which could then give me the torque? And if so, how?

Yes.

First calculate the angular acceleration from the velocity of the rope and the dimensions of the drum.

Then what equation relates torque and angular velocity?
 
Last edited:
  • #5
CWatters
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PS: The Torque will not be the value calculated earlier because part iii) says "at a constant speed".
 

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