Torque & Inertia calculation for a wheel

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George_J
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Hello!

Before I start I want to apologize for my english and not having a scanner (lol).

I'm calculating the torque needed to rotate a wheel* around its own axis from above, ( see the link at the end of post). I have quite an good idea to how I'm supposed to calculate it but I feel that something is missing.
10if1jk.jpg


My picture explains it in a very simplistic matter, the wheel is intersecting the ground just to magnify the contact surface and the wheel is also bearing a Force (m*g) and also a torque. The contact surface I explained as a simple rectangle with a center, the longest path is from the center to one of the corners, will be the lever for the torque applied. I hope my picture explains it better than I do. The path can be calculated easily with Pythagoras and the Torque in this case is called ''force couple'' or ''pure moment'' , sadly I don't know the exact name since I'm studying in Swedish. & with that I can calculate the power needed for this rotation.

The purpose is to purchase a motor that can handle the torque/power. I could always just buy a very strong motor but that is not the purpose of my ''research''. But anyhow I really think something is missing here. The inertia perhaps ? I can't put my finger on it and I'm very bad at dynamics..

I have datasheets to all available motors, which includes their torque, inertia and much more, I just need some hints in what is missing in my calculation..
For those wondering I'm building a monorail robot, and it should approximately weigh 30ish kg. The wheels are supposed to be 10-15 cm in diameter.

Now I humbly ask for your help, and I hope I don't come over as an arrogant person asking such a big favor..

* http://www.cleaningshop.com.au/contents/media/l_19097_utility_cart_wheels.jpg
(This picture is not accurate the axis of the wheel will be aligned with the wheels center. As of now anyway.)
 
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Hello George, and :welcome:

What I am missing here is the required acceleration: the torque not only has to overcome friction, but also has to provide some useful acceleration I suppose. If the wheels are any good and the surface is smooth, I expect the acceleration to need more torque than the friction !

I don't follow the way you (ab?)use the extensiveness of the contact surface. Better to assume its size doesn't come into the calculations.