Torque on a rotating solid conducting cylinder in B field

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SUMMARY

The discussion focuses on calculating the torque on a solid conducting cylinder rotating in a uniform magnetic field, as outlined in Panofsky's problem 10.3. The key equations involve the current density j defined as j = σ(u × B) and the torque τ expressed as τ = ∫(ρv × B)dV. A participant points out that the integral presented for torque appears to represent net force instead, indicating that the net torque is not zero, contradicting the initial assumption. The expressions for current density and drift velocity are confirmed to be correct, provided v denotes the drift velocity of charge carriers.

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  • Familiarity with the concepts of torque and angular momentum in physics
  • Knowledge of solid-state physics, particularly conductivity and charge carriers
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merrypark3
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Homework Statement


panofsky 10.3

Find the torque on a solid conducting cylinder rotating slowly in a uniform magnetic field perpendicular to the axis of the cylinder.





The Attempt at a Solution



let the radius of cylinder r, and the conductivity is σ, the rotating angular velocity is \stackrel{\rightarrow}{ω}

j=σ(u×B)=ρv=σ((ω×r)×B)
\stackrel{\rightarrow}{j}=σ((\stackrel{\rightarrow}{ω}×\stackrel{\rightarrow}{r}) ×\stackrel{\rightarrow}{B})=ρ\stackrel{\rightarrow}{v}


\stackrel{\rightarrow}{τ}=∫(ρ\stackrel{\rightarrow}{v}×\stackrel{\rightarrow}{B} )dV=0

Homework Statement



Is it right?
 
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merrypark3 said:
j=σ(u×B)=ρv=σ((ω×r)×B)
\stackrel{\rightarrow}{j}=σ((\stackrel{\rightarrow}{ω}×\stackrel{\rightarrow}{r}) ×\stackrel{\rightarrow}{B})=ρ\stackrel{\rightarrow}{v}\stackrel{\rightarrow}{τ}=∫(ρ\stackrel{\rightarrow}{v}×\stackrel{\rightarrow}{B} )dV=0
The net torque will not be zero. Your last integral looks like the net force rather than the net torque. Otherwise your expressions look ok to me if ##\vec{v}## denotes the drift velocity of charge carriers. I don't think using ##\rho \vec{v}## for ##\vec{j}##will help much.
 
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