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Cheapo2004

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At the moment before a diver jumps from a diving board, a force of 1.200 X 10^3 N is exerted on teh diver at an angle of 90 degrees to the board. This force produces a torque in the clockwise direction. At the same time, the diver's weight produces a torque in the counterclockwise direction. The diver's mass is 60 kg, and the angle between the diver's weight and the board is 87.7 degrees. If the net torque acting on the diver is 2985 N*m clockwise, what is the length of the diving board?

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For the first part, doesn't my teacher mean NEGATIVE 2985 N because its in the clockwise direction?

Anyways, here's the info i got out of that:

Tnet = 2985 N*m

F1 = 1200 N

F2 = ?

Degrees1 = 90

Degrees2 = 87.7

Any ideas about what equations i could use for this, or what it even looks like?!