Torque & Rotational Motion Question

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SUMMARY

The discussion revolves around a physics problem involving torque and rotational motion related to a diver on a diving board. A force of 1.200 x 10^3 N is applied at a 90-degree angle, generating a clockwise torque, while the diver's weight, at an angle of 87.7 degrees, produces a counterclockwise torque. The net torque is given as 2985 N*m clockwise. Participants express confusion regarding the interpretation of torque directions and the relevance of the diving board's length in calculating the forces involved.

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  • Understanding of torque and its calculation
  • Knowledge of forces and angles in physics
  • Familiarity with the concept of center of mass (CM)
  • Basic principles of rotational motion
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  • Learn about the relationship between force, mass, and weight in physics
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Cheapo2004
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Ok, here's a problem on a quiz that i just can't figure out. I'm having trouble drawing it in the first place:
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At the moment before a diver jumps from a diving board, a force of 1.200 X 10^3 N is exerted on the diver at an angle of 90 degrees to the board. This force produces a torque in the clockwise direction. At the same time, the diver's weight produces a torque in the counterclockwise direction. The diver's mass is 60 kg, and the angle between the diver's weight and the board is 87.7 degrees. If the net torque acting on the diver is 2985 N*m clockwise, what is the length of the diving board?
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For the first part, doesn't my teacher mean NEGATIVE 2985 N because its in the clockwise direction?
Anyways, here's the info i got out of that:

Tnet = 2985 N*m
F1 = 1200 N
F2 = ?
Degrees1 = 90
Degrees2 = 87.7

Any ideas about what equations i could use for this, or what it even looks like?!
 
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Still need help :frown:
 
Cheapo2004 said:
Ok, here's a problem on a quiz that i just can't figure out. I'm having trouble drawing it in the first place:
-----------
At the moment before a diver jumps from a diving board, a force of 1.200 X 10^3 N is exerted on the diver at an angle of 90 degrees to the board. This force produces a torque in the clockwise direction. At the same time, the diver's weight produces a torque in the counterclockwise direction. The diver's mass is 60 kg, and the angle between the diver's weight and the board is 87.7 degrees. If the net torque acting on the diver is 2985 N*m clockwise, what is the length of the diving board?
------------

For the first part, doesn't my teacher mean NEGATIVE 2985 N because its in the clockwise direction?
Anyways, here's the info i got out of that:

Tnet = 2985 N*m
F1 = 1200 N
F2 = ?
Degrees1 = 90
Degrees2 = 87.7

Any ideas about what equations i could use for this, or what it even looks like?!
Are you sure you have stated the problem correctly? I can't draw it either. A force exerted on the diver can only produce a torque on the diver. Is the first stated force on the diver a force exerted by the board, or is it the total force acting on the diver? The divers weight acts on the diver and can only produce a torque on the diver. Torque is always in reference to some point of rotation. What point are we to use? The logical point is the diver's CM, in which case the weight produces no torque, so all of the torque is due to the first force, a force that can never be found unless we know the distance between the line of the force and the point of rotation. Even if we could find this force, torques applied to the diver have absolutely nothing to do with the length of the board. As stated, I am afraid this is nonsense.
 

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