- #1
Bikerz
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The fuel storage yard is separated from the main plate by a swingbridge (swinging in a horizontal plane). The motor driving the briudge has to swing through an angle of 90degrees in 120seconds. The bridge accelerates uniformly for 40s then moves at a constant velocity, decelerating uniformly to rest in the final 20 s. The rotaing components of the bride have an equivalent moment of inertia of 400kgm² and feels a constand resisting torque of 3kN,. Find Torque of 3 stages of montion?
How do I go about this?
Which equations should I be using?
Torque = Inertia x Angular acceleration
Angular Velocity = Angle/dt (Time I presume)
I have done
sa=((V+0)/2)40=20V
sb=((V+V)/2)60=60V
sc=((0+V)/2)20=10V
I could then do
W=dØ/dt
Then times by Inertia (400)
I get
a-200N
b-400N
c=200N
This seems too easy and whast the resisting torque value for? Do I just add this to part a, ignor for part b and take off for part c?
Tho I'd get a negitive vale for c then?
Cheers
Sheldon
How do I go about this?
Which equations should I be using?
Torque = Inertia x Angular acceleration
Angular Velocity = Angle/dt (Time I presume)
I have done
sa=((V+0)/2)40=20V
sb=((V+V)/2)60=60V
sc=((0+V)/2)20=10V
I could then do
W=dØ/dt
Then times by Inertia (400)
I get
a-200N
b-400N
c=200N
This seems too easy and whast the resisting torque value for? Do I just add this to part a, ignor for part b and take off for part c?
Tho I'd get a negitive vale for c then?
Cheers
Sheldon