The problem involves two men carrying a 25.0 ft telephone pole weighing 200.0 lb, with the center of gravity located 10.0 ft from the right end. To determine the weight each man must support, the equation (M1X1) + (M2X2) = 200 lb is utilized, where M1 and M2 are the weights supported by each man, and X1 and X2 are their respective distances from the center of gravity. The discussion emphasizes the importance of calculating net torque, as it is essential for solving equilibrium problems involving forces and distances.
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Phox said:Homework Statement
Two men are carrying a 25.0 ft telephone pole that weighs 200.0 lb. If the center of gravity of the pole is 10.0 ft from the right end, and the men lift the pole at the ends, how much weight must each man support?
Homework Equations
?The Attempt at a Solution
(M1X1)+(M2X2) = 200 lb
I'm really confused here..