Torricelli's Law (Seperable DE Application)

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SUMMARY

The discussion focuses on applying Torricelli's Law to determine the time required for gasoline to drain from a spherical tank with a radius of 4 feet and a bottom hole of radius 1 inch. The equation used is dVolume/dTime = -a(2gy)^(1/2), where the cross-sectional area A(y) is expressed as A(y) = ∏(4^2 - (4-y)^2). However, there is confusion regarding the validity of this area expression, particularly at the top of the sphere where the area should be zero when y equals 4. Clarification is sought on the correct formulation of the cross-sectional area.

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  • Understanding of Torricelli's Law in fluid dynamics
  • Knowledge of calculus, specifically separable differential equations
  • Familiarity with the geometry of spheres
  • Basic principles of fluid flow and cross-sectional area calculations
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  • Review the derivation of Torricelli's Law and its applications in fluid dynamics
  • Study the geometry of spheres and how to calculate cross-sectional areas at various heights
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PsychonautQQ
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Homework Statement


A spherical tank of radius 4(ft) is full of gasoline when a circular bottom hole with radius 1 in. is opened. How long will be required for all the gasoline to drain from the tank?



Homework Equations



dVolume/dTime = -a(2gy)^(1/2)

The Attempt at a Solution


Right now I'm trying to find an equation to express the cross sectional area of the sphere in terms of y. The answer solution manual I am looking out says that A(y) = ∏(4^2 - (4-y)^2). However, I don't see how this can be correct as that would mean the cross section area when y=4 is equal to ∏*16, which is obviously false, because the top of a sphere should have cross sectional area of 0. It works when you enter 0 in for y however. Help?
 
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PsychonautQQ said:

Homework Statement


A spherical tank of radius 4(ft) is full of gasoline when a circular bottom hole with radius 1 in. is opened. How long will be required for all the gasoline to drain from the tank?

Homework Equations



dVolume/dTime = -a(2gy)^(1/2)

The Attempt at a Solution


Right now I'm trying to find an equation to express the cross sectional area of the sphere in terms of y. The answer solution manual I am looking out says that A(y) = ∏(4^2 - (4-y)^2). However, I don't see how this can be correct as that would mean the cross section area when y=4 is equal to ∏*16, which is obviously false, because the top of a sphere should have cross sectional area of 0. It works when you enter 0 in for y however. Help?

The sphere has radius 4, so if its bottom is at y = 0 then its center is at y = 4 and its top is at y = 8.
 
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