Trajectory in magnetic undulator

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SUMMARY

The discussion focuses on deriving the trajectory r(t) for a charged particle in a magnetic undulator using the equations of motion. The equations provided are x'' = w * y' * cos(a*x), y'' = -w * x' * cos(a*x), and z'' = 0. The participant successfully integrates the second equation to find y' but struggles to progress further due to the complexity introduced by the magnetic field. The use of Fourier transformation is suggested as a potential method to analyze the periodic nature of the trajectory.

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  • Understanding of classical mechanics and equations of motion
  • Familiarity with magnetic fields and their effects on charged particles
  • Knowledge of Fourier transformation techniques
  • Basic calculus for integration and differential equations
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Franky4
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Homework Statement



I am asked to find r(t) for a charged q particle in an magnetic undulator. Wrote down these equations:
x'' = w* y' *cos(a*x) (1)
y'' = -w* x' *cos(a*x) (2)
z'' = 0 (3)

r(0) = (x0, y0, z0); r(0)' = (x0', y0', z0').

Homework Equations


Not sure how to go on solving these.

The Attempt at a Solution


z(t) is obvious. I am able to integrate (2) once to find y' = -w/a *sin(a*x) + C. Plugging it into (1) doesn't seem to do any progress, since I get x'' = - w^2 /a *sin(a*x)*cos(a*x) + C*w*cos(a*x). Because particle is in magnetic field, it's known that sqrt(x'^2 + y'^2 + z'^2) = constant from r(0)', but not sure how to use it to my advantage.
 
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A typical undulator would allow some approximations that make the equations easier (e. g. "x' does not change much").
A Fourier transformation could give interesting results (the path is like a sine-curve or a bit similar to a circle, but certainly periodic), but I don't know if it works.
 

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