1. The problem statement, all variables and given/known data a projectile is shot from the edge of a cliff 125m above ground level with an initial speed of 105m/s at an angle of 37 degrees with the horizontal axis. 1.determine the time taken by the projectile to hit ground. 2.determine the range X of the projectile as measured from the base of the cliff. 3.find the horizontal and verticle components of its velocity. 4.find the magnitude of the velocity 5.the angle made by the velocity vector with the horizontal 2. Relevant equations R=(Vo^2sin2(theta))/g 3. The attempt at a solution 1. Vf=Vo+at 0=63.19m/s+-9.8m/s^2t -63.19m/s=-9.8m/s^2t t=6.45s thats the time for the projectile going up the Y axis y=125+ 63.19m/s(6.45s)+-4.9(6.45s)^2 y= 328m d=1/2(a)(t)^2 328 = 4.9t^2 t^2=66.94 t=8.18s time going down the Y axis time total=8.18s+6.45s=14.63s 2. Dx=v*t Dx=83.86m/s*14.63s Dx=1226.87m 3. sin(37)(105m/s)=63.19m/s y cos(37)(105m/s)=83.86m/s x 4. 5. as you can tell, I need a lot of help in completing this problem.