Transfer function-leading and lagging

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SUMMARY

The transfer function discussed is G(jw) = 1/(1-j), where j represents the imaginary unit. The output to input amplitude ratio is determined to be 1/sqrt(2), indicating that the output leads the input by 45 degrees. The magnitude of G(jw) is calculated using the formula |G(jw)| = sqrt(Re^2 + Im^2), where Re is the real part and Im is the imaginary part. The phase relationship is derived using the arc tangent function, specifically arc tan(Im/Re), with careful attention to the signs of the numerator and denominator.

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  • Understanding of transfer functions in control systems
  • Familiarity with complex numbers and the imaginary unit j
  • Knowledge of amplitude ratios and phase relationships
  • Basic proficiency in trigonometric functions, particularly arc tangent
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If we have the transfer function:
G(jw)=1/(1-j) where j=imaginary number

What is the output to input amplitude ratio and the phase relationship.

I'm confused about which one is the output and which is the input. I thought jw, the argument, is the input and everything on the right hand side is the output?

If so, this is not getting my the right answers that output to input amplitude ratio=1/sqrt(2) and that output leads input by 45 degrees.
 
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pyroknife said:
If we have the transfer function:
G(jw)=1/(1-j) where j=imaginary number

What is the output to input amplitude ratio and the phase relationship.

I'm confused about which one is the output and which is the input. I thought jw, the argument, is the input and everything on the right hand side is the output?

If so, this is not getting my the right answers that output to input amplitude ratio=1/sqrt(2) and that output leads input by 45 degrees.

G(jw) = output/input.

The magnitude of G(jw) = |G(jw)| = sqrt(Re^2 + Im^2)
where Re = "real part" and I am = "imaginary part".

The phase of output/input is arc tan(Im/Re). Be careful to preserve the sign of the numerator and the denominator. Arc tan(-b/a) is not the same angle as arctan(b/-a).
 

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