I have to find the transfer function of a linearly and ideally operating OP Amp.
The Attempt at a Solution
I know that the current through the capacitor, R1, and R2 is the same, so i=C(dv/dt) = Vin/R1 = (VIN-V0)/R2, where do I go from here? Is the transfer function just V0/VIN in terms of R1, R2, C and dv/dt? When I equate the second and third equations I get V0/VIN = 1-(R2/R1) but i'm not sure if this is right.
For the second part, I assume I just find a value of R1 that gives a value of A = 20-& in the equation VIN=A(gain) V0