Is the Voltage at Point A Still 5V with V_in at 0 in a Transistor-Diode Circuit?

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In a transistor-diode circuit with an input voltage (V_in) of 0, there is no current flowing through the 1000 ohm resistor, resulting in no voltage drop from the base to emitter. Consequently, the transistor remains off, leading to an open circuit condition. As a result, no current flows through the 100 ohm resistor either. Therefore, the voltage at point A remains at 5V. This confirms the understanding of the circuit's behavior under these conditions.
Clandry
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I just wanted to see if I am understanding this circuit correctly.
Let's say the input voltage (V_in) is 0.
This means:
1) no current through the 1000 ohm resistor
2) no 0.7V drop from the base to emitter
3) transistor is pretty much off
4) The circuit is open, thus no current goes through the 100 ohm resistor either
5) voltage at A must be 5V
 

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Correct.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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