Transistor Resistance: Find Current & Formula

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SUMMARY

Transistors, specifically Bipolar Junction Transistors (BJTs), exhibit non-linear voltage-to-current characteristics, which complicates the concept of resistance. The base-emitter junction functions as a diode requiring approximately 0.7V to conduct significant current, resulting in a voltage drop that affects the overall circuit current. In simulations, the current measured was 22.52mA, lower than the expected 30mA due to this voltage drop. Understanding both static (R=V/I) and dynamic (r=dV/dI) resistances is crucial for accurate analysis and design.

PREREQUISITES
  • Understanding of Bipolar Junction Transistor (BJT) operation
  • Familiarity with diode characteristics and voltage drops
  • Knowledge of static and dynamic resistance concepts
  • Basic circuit analysis skills, including Ohm's Law
NEXT STEPS
  • Study the current-voltage characteristics of BJTs and FETs
  • Learn about static and dynamic resistance calculations in semiconductor devices
  • Explore simulation tools for circuit analysis, such as LTspice or Multisim
  • Investigate the impact of temperature on transistor performance and characteristics
USEFUL FOR

Electronics engineers, circuit designers, students studying semiconductor physics, and anyone interested in understanding transistor behavior in electronic circuits.

LtIvan
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Do transistors give a certain resistance?
If so how do you find this resistance?
Say Hypothetically for the following example. Refer to (fig.1).
The resistor's value is 100Ω, source is 3V.
Say if the transistor wasn't there, the amp would be 0.03A or 30mA.
But when I run this in a simulation, the amp across the ciruit is 0.02252A or 22.52mA.
How is the transistor affecting the current and is there a formula?
 

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The base-emitter junction inside the transistor is actually a diode. This diode needs at least 0.7V across it before it will conduct appreciable current. This leaves 2.3V or less across the resistor. The 22.53mA shows that the actual voltage drop across the base-emitter diode is 0.748V, which is reasonable for a small transistor.
 
Thankyou.
That helped a lot.
 
Tom.G said:
The base-emitter junction inside the transistor is actually a diode. This diode needs at least 0.7V across it before it will conduct appreciable current.
Looking at the current-voltage characteristics of the B-E path (as for any pn junction) we see a typical exponential function with a current even for voltages as low as 0.1 volt. What is an "appreciable" current? I think, it is necessary again to mention that the pn junction does not "suddenly" open at a voltage of 0.7 V (as some newcomers might think).
 
@LvW

I agree. The 0.7V is just a 'typical' rule-of-thumb used during a quick-look circuit evaluation. Especially for design, a look at the characterisric curves is essential. (as the OP 0.748V example points out!)
 
LtIvan said:
Do transistors give a certain resistance?
If so how do you find this resistance?

Each transistor (BJT and FET) as well as each semiconductor device (diode) has a strong non-linear voltage-to-current characteristics.
Therefore, speaking about "resistances" it is very important strongly to discriminate between STATIC (R=V/I) and DYNAMIC (r=dV/dI=v/i) resistances.
So - what is your problem? A transistor is a three-terminal device and we can define two resistances (static, dynamic) at the input as well as at the output port.
 

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