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Intrinsic resistance of a transistor

  1. Feb 28, 2009 #1
    In my circuits class we were talking about bipolar transistors and our prof. mentioned that every bipolar resistor has an intrinsic emitter resistor. So, I tried modeling a couple of circuits in SPICE to see if I can replace the transistor with another circuit (voltage source, current source, and the intrinsic resistor). However, I never got to that point, because I could not find the correct value of this resistor. In class he just said that we need the change in collector voltage (delta Vc) and change in emitter voltage (delta Ve) to figure it out. That doesn't make any sense to me. Don't you need a current to find that?
    Does anyone have an explanation of how to find the intrinsic emitter resistance of a bipolar transistor?

  2. jcsd
  3. Feb 28, 2009 #2
    re = Vt/Ie.

    Vt = kT/q; k = 1.38e-23 joule/Kelvin, T = temperature in Kelvin, q = 1.602e-19 coulomb.

    Ie = dc or bias value of emitter current

  4. Feb 28, 2009 #3

    Thanks for your answer. This will help me to double check if I'm right with my approximation. However, there should be another way to get to the intrinsic emitter resistance.
    According to the attached picture, the resistance can be approximated with delta Vc and delta Ve (the deltas are obtained by sweeping Vb over a certain range).
    Any ideas how this is done?

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