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Does anyone have an explanation of how to find the intrinsic emitter resistance of a bipolar transistor?

Thanks

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- Thread starter adiman1984
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- #1

- 2

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Does anyone have an explanation of how to find the intrinsic emitter resistance of a bipolar transistor?

Thanks

- #2

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Vt = kT/q; k = 1.38e-23 joule/Kelvin, T = temperature in Kelvin, q = 1.602e-19 coulomb.

Ie = dc or bias value of emitter current

Claude

- #3

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Thanks for your answer. This will help me to double check if I'm right with my approximation. However, there should be another way to get to the intrinsic emitter resistance.

According to the attached picture, the resistance can be approximated with delta Vc and delta Ve (the deltas are obtained by sweeping Vb over a certain range).

Any ideas how this is done?

Thanks

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